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How to compute crystal deviation seconds per day in Python using UliEngineering

You can easily compute the time deviation per day from crystal frequency accuracy using the UliEngineering Python library:

crystal_deviation_seconds_per_day.py
from UliEngineering.Electronics.Crystal import crystal_deviation_seconds_per_day

# Compute deviation for 10 ppm crystal
deviation = crystal_deviation_seconds_per_day("10ppm")
print(f"Deviation (10ppm): {deviation:.2f} s/day")

# Compute deviation for 50 ppm crystal
deviation = crystal_deviation_seconds_per_day("50ppm")
print(f"Deviation (50ppm): {deviation:.2f} s/day")

# Compute deviation for 100 ppm crystal
deviation = crystal_deviation_seconds_per_day("100ppm")
print(f"Deviation (100ppm): {deviation:.2f} s/day")

Example output

crystal_deviation_seconds_per_day_output.txt
Deviation (10ppm): 0.86 s/day
Deviation (50ppm): 4.32 s/day
Deviation (100ppm): 8.64 s/day

The crystal deviation seconds per day calculation determines the time error that accumulates over one day due to crystal frequency inaccuracy. This is essential for timing applications, clock synchronization, and understanding the long-term accuracy of crystal oscillators. The deviation is proportional to the frequency accuracy specified in parts per million (ppm) and scales linearly with time.

The deviation is computed using the formula: $\Delta t = \text{ppm} \times 10^{-6} \times T$, where $\Delta t$ is the time deviation, $\text{ppm}$ is the frequency accuracy in parts per million, and $T$ is the time interval (86400 seconds for one day). For example, a 10 ppm crystal will deviate by 0.86 seconds per day, which is significant for applications requiring precise timing over extended periods.

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