使用 UliEngineering 在 Python 中计算电阻器功耗

在此示例中，我们将使用我们的科学和工程 Python 库 UliEngineering 计算流过30 mA 恒定电流的1 kΩ 电阻器的功耗。

现在我们可以使用 power_dissipated_in_resistor_by_current() 计算电阻器功耗

resistor_power_example.py

from UliEngineering.EngineerIO import auto_print
from UliEngineering.Electronics.Resistors import *
# 只计算值：
power = power_dissipated_in_resistor_by_current("1 kΩ", "30 mA") # power = 0.9

# 打印值：打印：打印 "900 mW"
auto_print(power_dissipated_in_resistor_by_current, "1 kΩ", "30 mA")

from UliEngineering.EngineerIO import auto_print
from UliEngineering.Electronics.Resistors import *
# 只计算值：
power = power_dissipated_in_resistor_by_current("1 kΩ", "30 mA") # power = 0.9

# 打印值：打印：打印 "900 mW"
auto_print(power_dissipated_in_resistor_by_current, "1 kΩ", "30 mA")

由于结果是 900 mW，你可以推断你需要使用功率额定值至少为一瓦的电阻器。

注意你可以向大多数 UliEngineering 函数传递数字（如 0.03）或字符串（如 30 mA 或 0.03 A）。SI 前缀如 k 和 M 会自动解码

如果你知道电阻器两端的电压，可以使用 power_dissipated_in_resistor_by_voltage()。假设电阻器两端有 1V 压降：

resistor_power_voltage_example.py

from UliEngineering.EngineerIO import auto_print
from UliEngineering.Electronics.Resistors import *
# 只计算值：
power = power_dissipated_in_resistor_by_voltage("1 kΩ", "30 mA") # power = 0.001

# 打印值：打印：打印 "1.00 mW"
auto_print(power_dissipated_in_resistor_by_voltage, "1 kΩ", "30 mA")

from UliEngineering.EngineerIO import auto_print
from UliEngineering.Electronics.Resistors import *
# 只计算值：
power = power_dissipated_in_resistor_by_voltage("1 kΩ", "30 mA") # power = 0.001

# 打印值：打印：打印 "1.00 mW"
auto_print(power_dissipated_in_resistor_by_voltage, "1 kΩ", "30 mA")

所以在这种情况下功耗极低 - 只有 1.00 mW - 对大多数实际应用无关紧要。

在许多情况下，你也可以向 UliEngineering 函数传递 NumPy 数组：

resistor_power_numpy_example.py

from UliEngineering.EngineerIO import format_value
from UliEngineering.Electronics.Resistors import *
import numpy as np

# 计算值：
resistors = np.asarray([100, 500, 1000]) # 100 Ω, 500 Ω, 1 kΩ
power = power_dissipated_in_resistor_by_voltage(resistors, "30 mA") # power = 0.001

# power = [9.0e-06 1.8e-06 9.0e-07]

from UliEngineering.EngineerIO import format_value
from UliEngineering.Electronics.Resistors import *
import numpy as np

# 计算值：
resistors = np.asarray([100, 500, 1000]) # 100 Ω, 500 Ω, 1 kΩ
power = power_dissipated_in_resistor_by_voltage(resistors, "30 mA") # power = 0.001

# power = [9.0e-06 1.8e-06 9.0e-07]

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